saberrider wrote:At 1 g it is not possible to climb straight up?

Ask a technical question, get a technical answer. My previous answer was very specific to turn rate so now I will go into more detail about 1G.

It means the total lifting ability of the plane is matching the total mass of the plane times the gravitational accel, not that you are perfectly opposed to gravity. In vertical flight the plane is making zero net lift. If you were in true net 1G vertical climbing flight then you would be pulling out of the vertical while SLOWING DOWN at a rate of ~19kt/sec and then only in that one instance.

The steady state of a climb attitude (no accelerations) means the Nz (G force through the "vertical axis" of the aircraft) is equal to the Cosine of the pitch angle, 1G Nz at 0 degrees pitch and 0G Nz at 90 degrees pitch. In a theoretical steady state vertical climb, no change in airspeed, then you have -1G Nx (down the long axis of the aircraft). So, in a non-level condition then having 1G Nz means a pitch change. If you want zero G Nx then it is either level flight, a dive, or a decelerating climb (with Nx deceleration relative to the Sine of the pitch angle). If you don't care about Nx then 1 Nz can result in all kinds of conditions, including inverted where the aircraft will turn with 2G even though only 1Nz is felt as Nz doesn't care about where gravity is.

I have to run right now, let me know if you need more explanation.